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x^2 + 12xy + 35y^2 factor completely
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HEyyy!
hiiiiiiiii hun !
\[(x+5 y) (x+7 y) \]
how was the wedding sweetie?
thank u but how do u get tht ?
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IT was cool. :D
yaay
The middle and last terms are positive, and there's no coefficient in front of the x^2, so we're looking for something in the form of (x + ?y)(x + ?y) We now just have to find two numbers whose product is 35 and whose sum is 12. The pair that works is 7 and 5. (x + 5y)(x + 7y)
thankk uuuu lozl missed u all day today hahahahaha
haha, i was working on 2.11 scored 20/20
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yaaaay :D
lozl i wishh i cud give u another medal dammit hahaha
haha
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