Question

A certain merry go round is accelerated uniformly from rest and attains an angular speed of 0.4 rad/sin the first 10 seconds. If the net torgque is 2000 N.m, what is the moment of inertia of the merry go round?

Answer 1

First, we can find the average angular acceleration\[\alpha=\Delta \omega/\Delta t=(.4rad/s)/10s=.04rad/s^2\]You also know that \[T=I*\alpha\]Therefore\[I=T/\alpha=2000/.04=50000\]