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Mathematics 17 Online
OpenStudy (unklerhaukus):

-e^(iπ)

OpenStudy (anonymous):

\[-e^{i \pi}\]

OpenStudy (anonymous):

Uno

OpenStudy (anonymous):

- (cos pi + i sin pi)

OpenStudy (anonymous):

use euler's formula perhaps? \[e^{i\pi} = cos\pi +isin\pi\]

OpenStudy (anonymous):

yes

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