Question

den shaped like rectangle. perimeter is 432 ft. lenght is 8 tmes as long as width. find length and width.

Answer 1

let x= width, y= length
2x+2y=432
since length is 8 times longer than width
y=8x
now substitute
2x+2(8x)=423
2x+16x=432
18x=432
x=24
now y=8x
so y=192
therefore width is 24 ft
length=192 ft

Answer 2

Permeter=p=432=2w+2L, but L=8w therefore
432=2w+2(8w)
432= 2w+16w=18w
432/18=24ft=w ........ans
L=8w=8(24)=192 ft .....ans