den shaped like rectangle. perimeter is 432 ft. lenght is 8 tmes as long as width. find length and width.

Question

anonymous · Answer

let x= width, y= length
2x+2y=432
since length is 8 times longer than width
y=8x
now substitute
2x+2(8x)=423
2x+16x=432
18x=432
x=24
now y=8x
so y=192
therefore width is 24 ft
length=192 ft

anonymous · Answer

Permeter=p=432=2w+2L, but L=8w therefore
                      432=2w+2(8w)
                       432= 2w+16w=18w
                       432/18=24ft=w  ........ans
L=8w=8(24)=192 ft   .....ans