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a^x - b^x / x as x tends to 0
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Do you know the derivative of a^x wrt (with respect to) x?
yes
xlna?
would we apply l'hospital rule?
Good then write \[\frac{a^x - b^x}{x} = \frac{a^x - 1}{x - 0} - \frac{b^x - 1}{x - 0}\] Then notice the the limit of each of these terms is the derivate of a^x and b^x respectively evaluated at x=0.
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yea now it is simple
thank u
Sure thing.
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