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Why is that when i am trying to use the shell method for this problem: y=5x+6 and y=x^2, rotated about the x axis, i have to break it up into two integrals.
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well, lets draw it :)
|dw:1316890480442:dw|
since you have a odd spot that you have to account for, its best to do it in parts
|dw:1316890571158:dw|
ah, i see that small portion below y=1
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the equations for the area change at that point :)
so the radius of that would still be y
correct, the radius of the shell doesnt change; just the equations that define the area
but what would be the heigh, woudl it just be sqrtx-0
lets turn this to see it in a normal view point
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