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Mathematics 11 Online
OpenStudy (anonymous):

Factor: (51t − 16t^2) − 38

OpenStudy (oaktree):

OK. So, first you want the t^2 term to be positive, right?

OpenStudy (oaktree):

So, you simplify the parentheses and you have -16t^2+51t-38.

OpenStudy (oaktree):

Now you divide by (-1) and you have 16t^2-51t+38

OpenStudy (oaktree):

Now you can factor it normally and you get (t-2)(16t-19) as your final answer.

OpenStudy (oaktree):

Good?

OpenStudy (anonymous):

hey sorry i was away from my computer let me look over your steps really quick :)

OpenStudy (anonymous):

hey yeah, that works, thank you!

OpenStudy (oaktree):

No problem.

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