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solve for x e^(3-4x) = 5
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x=l(n(5)-3)/(-4)
x=(ln(5)-3)/(-4)= 0.3476...
i got lne^(3-4x)=ln5
right.
so shouldnt it be 3-5x=ln5
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3-4x = ln5
what im not sure is to do next
3-4x = 1.609
Solve for x.
My teacher is looking for exact values
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-ln5+3 / 4 = x
would that be right?
i guess so...
so ln would be the more appropriate option than using log
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