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Mathematics 19 Online
OpenStudy (anonymous):

solve w^4-12w^2-2=0

jhonyy9 (jhonyy9):

\[w ^{2}=x\]

jhonyy9 (jhonyy9):

\[x ^{2}-12x-2=0\]

jhonyy9 (jhonyy9):

x_1,_2=(12+/- sqrt(144+8))/2 =(12+/- sqrt(152))/2

jhonyy9 (jhonyy9):

x_1,_2=(12+/- 2sqrt(38))/2 = 6+/- sqrt(38)

jhonyy9 (jhonyy9):

\[w ^{2}= 6-\sqrt(38)\]

jhonyy9 (jhonyy9):

w_1,_2= +/- sqrt(6-sqrt38)

jhonyy9 (jhonyy9):

\[w ^{2}= 6+ \sqrt(38)\]

jhonyy9 (jhonyy9):

w_3,_4= +/- sqrt(6+sqrt(38)

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