Question

Math Check:

Use the quadratic equation to solve:
2x^2-3x=-5

I got\frac{3\pm i \sqrt{49}}{4}\

Answer 1

grr\[\frac{3\pm i \sqrt{49}}{4}\ \]

Answer 2

2x² -3x +5 = 0
delta: (-3)² - 4*5 *2 =
= 9 - 40
= -31
~ Are you sure the equation is 2x² -3x+5 =0
not 2x²-3x-5 =0 ?

Answer 3

well it was 2x^2-3x=-5, that translates to 2x-3x+5-0 doesn't it? :o

Answer 4

=0 not -0 sorry

Answer 5

so, If is 2x² -3x +5=0
delta = b² -4*a*c = -31
and \[(-b \pm \sqrt{\Delta})\div 2 *a =\]
\[(-(-3)\pm \sqrt{-31}) / 4 =\]
\[(3\pm i \sqrt{31} )/ 4\]
\[x' = (3+ i \sqrt{31}) /4\]
\[x'' = (3- i \sqrt{31}) /4\]