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Mathematics 19 Online
OpenStudy (anonymous):

ln(e^3/5)

OpenStudy (anonymous):

ln and e^x are inverse operations so you just get 3/5

OpenStudy (anonymous):

the answer is not 2-ln5?

OpenStudy (zarkon):

\[\ln(e^{3/5})=3/5\]

OpenStudy (zarkon):

if the question was \[\ln\left(\frac{e^3}{5}\right)=\ln(e^3)-\ln(5)=3-\ln(5)\]

OpenStudy (anonymous):

that helped thankyou!

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