Question

Write the slope-intercept equation for the line that passes through (-3, -15) and is perpendicular to -6x + 8y = 3 Please show all of your work.

Answer 1

-6x + 8y = 3 ; a perp line is simply swap cooefs and
switch operators, and trash the constant

8x + 6y = C ; recalibrate with the given point for C
-3 -15
-24 -90 = -114

8x +6y = -114 ; then rearrange into slope,int format

Answer 2

thanks