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OpenStudy (anonymous):
What are the asymptotes of the hyperbola given by the equation x^2/144-y^2/4 = 1
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OpenStudy (amistre64):
it widens on the x
OpenStudy (amistre64):
2/12 = +- 1/6 x
OpenStudy (amistre64):
looks to be about right, since its centerd at the origin and when y=0, x=12
OpenStudy (amistre64):
slope is the 2/12
OpenStudy (anonymous):
Okay thank you!
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OpenStudy (amistre64):
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