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solve for x: (2x-5)^2=121
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x=8
careful here
\[(2x-5)^2=121\] \[2x-5=11\] or \[2x-5=-11\] so get two answers
ohhhh... right
4x^2-20x+25-121=0 4x^2-20x-96=0 D=b^2-4ac and if D>0 then |dw:1316970252725:dw|
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\[2x-5=11\] \[2x=16\] \[x=8\] or \[2x-5=-11\] \[2x=-6\] \[-3\]
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