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Mathematics 22 Online
OpenStudy (anonymous):

Use the Standard Normal Table and report your answer to 3 decimal places. The value of z such that P(|Z| < z) = 0.99 is [x].

OpenStudy (amistre64):

im thinking this has to do with a normal distribution ?

OpenStudy (anonymous):

yeahh i'm confused...

OpenStudy (amistre64):

the zscore for an area under the curve of .99 .... can be found on the table right?

OpenStudy (amistre64):

what is the table you are to use?

OpenStudy (amistre64):

OpenStudy (anonymous):

OpenStudy (amistre64):

OpenStudy (amistre64):

yours measures from the mean; so subtract .5 from .99 to fit iit

OpenStudy (amistre64):

.49 is what you need to find in the feild

OpenStudy (anonymous):

0.49? hmm lets see its an online hw so let me c if thats the answer :)

OpenStudy (amistre64):

|dw:1316973250280:dw|

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