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Mathematics 22 Online
OpenStudy (anonymous):

find lim x->0 x/tanx

OpenStudy (anonymous):

1

OpenStudy (anonymous):

lim x->0 sinx/x=1 lim x->0 cosx=1 so =1

OpenStudy (anonymous):

=>lim x->0 1/sec^2 x (apply L Hospital's rule since it is in 0/0 form) => 1/sec^2 0 => 1

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