Question

How do I solve this system by substituting?

t = 2r + 3
5r - 4t = 6

Answer 1

\[t = 2r + 3\]
\[t = \frac{6-5r}{-4} \]

Set t = t:
\[2r + 3 = \frac{6-5r}{-4} \]

-4(2r+3) = 6 - 5r

-8r-12 = 6 - 5r

3r = -18

r = -6
t = -9