Question

find the derivative
y= sin cubed rt of x + cubed root of sinx

Answer 1

\[y=\sin(\sqrt[3]{x})+\sqrt[3]{\sin(x)}=\sin(x^\frac{1}{3})+(\sin(x))^\frac{1}{3}\]
\[y'=(x^\frac{1}{3})'\cos(x^\frac{1}{3})+\frac{1}{3}(\sin(x))^{\frac{1}{3}-1}(\sin(x))'\]