Question

The difference of two positive numbers is 13. The larger is twice the smaller decreased by 7. Find the two numbers.
(smaller value)
(larger value)

Answer 1

20
33

Answer 2

it was 20 and 33. thanks though

Answer 3

ok so problem was l = 2s - 7 then.

Answer 4

d = 13 = l - s, where l = large number, s = small number
l = 2s - 7
d = 2s - 7 - s=13
= s - 7 = 13
s = 13 + 7
= 20

l = 2*20 - 7
= 40 - 7
= 33

Ans, s = 20, l = 33

Answer 5

thanks for showing how ya did it

Answer 6

np