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Mr. Wilson invested money in two accounts. His total investment was $31,000. If one account pays 9% in interest and the other pays 11% in interest, how much did he invest in each account if he earned a total of $3,090 in interest in 1 year? 11% interest $ 9% interest $
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put x = amount invested at 11% then 31, 000 - x is invested at 9% and solve \[.11x+.09(31000-x)=3090\] for x
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