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x^2+3/2x=3 solve by completing the square.
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x^2 + 3/2x = 3 x^2+3/2x + 9/16 -9/16 = 3 (x+3/4)^2 = 57/16 (x+3/4) = (+/-)((57^0.5)/4) x = ((57^0.5) - 3) / 4 or x = (-(57^0.5)-3) / 4
\[x ^{2} +3/2x =3\]
\[2x ^{2}+3x=6\]
\[2x ^{2}+3x-6=0\]
x_1,_2=(-3+=-sqrt(9+48))/4 =(-3+/-sqrt(57))/4
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