Mathematics
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OpenStudy (anonymous):
how do I solve the equation
5x-(2x-1)=2
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jhonyy9 (jhonyy9):
can i help to you ?
OpenStudy (anonymous):
yes, I have the awnser just need to know how I did it
jhonyy9 (jhonyy9):
comen i like you see how you will solve it
jhonyy9 (jhonyy9):
firstly you need to eéimine the parantheses
jhonyy9 (jhonyy9):
elimine
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OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
write me please
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
5x-2x-1=2
jhonyy9 (jhonyy9):
not is right
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OpenStudy (anonymous):
can you show me how to work this
jhonyy9 (jhonyy9):
ok
jhonyy9 (jhonyy9):
when you have -(-1) what will result to you
OpenStudy (anonymous):
+1
jhonyy9 (jhonyy9):
yes right comen make it now
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OpenStudy (anonymous):
5x-2x+1=2
jhonyy9 (jhonyy9):
yes and ...
OpenStudy (anonymous):
or 5x-10x+5=2
jhonyy9 (jhonyy9):
how you have got it this ? what you have wrote 5x-2x+1=2 is right
jhonyy9 (jhonyy9):
cont
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OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
continue this
OpenStudy (anonymous):
then subtract 1 from bothe sides?
jhonyy9 (jhonyy9):
yes and ?
OpenStudy (anonymous):
5x-2x=2
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jhonyy9 (jhonyy9):
why ?
OpenStudy (anonymous):
5x-2x=1 because i subtracted 1 fom both sides
jhonyy9 (jhonyy9):
make what you have wrote before
jhonyy9 (jhonyy9):
yes and 5x-2x=???
OpenStudy (anonymous):
5x-2x=2
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jhonyy9 (jhonyy9):
if you subtract 2 from 5 how many will remaind ?
OpenStudy (anonymous):
5x+1
jhonyy9 (jhonyy9):
no there you have wrote 5x-2x=1
so if you subtract 2 from 5 how many will remaind to you ?
OpenStudy (anonymous):
3
jhonyy9 (jhonyy9):
yes and the result ?