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OpenStudy (anonymous):
evaluate the derivative of the function at the point (pi/4,1) f(x)=sinx(sinx+cosx)
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OpenStudy (turingtest):
f'(x)=cosx(sinx+cosx)+sinx(cosx-sinx) f'(pi/4)=\[(\sqrt{2}/2)(\sqrt{2)}+0\]=1
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