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^3√(x²-9x)=-2?
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you mean 3rd root of (x^2-9x)=-2 ?
\[\sqrt[3]{x^2-9x}=-2\] ?????
x^2-9x=-8 x^2-9x+8=0 (x-1)(x-8)=0 x={1,8}
yes!
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