Question

g(x) = 1/(x+2)..find an equation for the tangent line to g(x) at the point (0, 1/2) ...please!

Answer 1

\[\lim_{h \rightarrow 0}=(x+2) - (x+h+2)/ h(x+h+2)(x+2) \]

Answer 2

Can you find the derivative of g(x), if you write 1/(x+2) as
\[(x+2)^{-1}\]

Answer 3

i have derivative of g(x) now....i believe it is -1/(x+2)^2 ...what would my first step be to find the tangent line