Question

Another question about absolute value inequalities:

|x - 3| > |2x + 1|

How can you go from the above step, to: (|x - 3|)^2 > (|2x + 1|)^2 ?

Answer 1

not sure why you would want to

Answer 2

but these problems are a royal pain, although i guess you can do it by graphing.

Answer 3

These problems are annoying me so much because I don't know any general technique I can use to deal with them.