Question

write the standard form of the equation of the line passing through the point (-3, 5) and perpendicular to the line -4x - 3y = -6

Answer 1

First you have to find the slope.
So, -3y = 4x - 6
y = -4/3x + 2
Slope of perpendicular line would be 3/4
Equation is:
y = 3/4 x + b
Substitute (-3, 5) into the equation and you get
5 = 3/4(-3) + b
Then find b and you have your equation