Question

Find the y-intercept of the tangent line at the point (-2, f(-2)) on the graph of.

f(x)=4x^2+3x+4

Answer 1

when x=-2 , y= 4(4)-6+4 = 14

so the point is (-2,14).

f'(x) = 8x +3

when x=-2, f'(-2) = -13

Answer 2

y-y1=m(x-x1)

Answer 3

y-14= -13(x-(-2) )

Answer 4

y= -13x -12

Answer 5

y intercept is (0,-12)

Answer 6

Thank you!