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Mathematics 21 Online
OpenStudy (anonymous):

lim x-->0 sinx/x^2+3x

OpenStudy (lgbasallote):

1/3

OpenStudy (anonymous):

sinx/(x^2+3x)

OpenStudy (lgbasallote):

lim x -> 0 sinx/x^2 +3x factorx.. x sinx/x (1/x+3)..sinx/x = 1 so all that's left is 1/x + 3..substitute..1/3 <<<just so you know the process ;)

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