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How many 4 person committees are possible from a group of 9 people if (a) There are no restrictions? (b) Both Jim and Mary must be on the committee? (c) Either Jim or Mary(but not boh) must be on the committee?
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Assuming there is no order (IE: the jobs aren't specific like President, secretary, etc.) you can use combinations to find the numbers. A) With no restriction, you have 9 people and choose 4 so 9C4=126 B) With Jim and Mary on, you have two spots filled. That leaves 7 people for the other two, IE: 7C2=21. C)If Jim is there and not Mary, you have 7C3=35. Ditto if Mary is there and not Jim. Thus you have 35+35=70 total commitees.
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