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Find the width of a rectangle with a perimeter of 90 and a length of 15
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perimeter=P=2L+2W=90 length=L=15 so we have 2L+2W=90 and L=15 2(15)+2W=90 solve for W
2w = 90 - 2*15 = 60 w = 30 width is greater than length maybe they shpould be reversed
15+W=90/2 (divided both sides by 2) 15+W=45 W=45-15=30
x=width 2x+30=90 2x=60 x=30 width = 30
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