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Differentiate the function y = f(x) = x+1 divided by x−1. there are no parentheses if it matters. my answer was -2 divided by x squared - 2x + 1. ( pretty sure i missed it)
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http://www.wolframalpha.com/input/?i=differentiate+%28+x%2B+1%29%2F+%28x-1%29
f(x) = u/v u = (x+1) v = (x-1) maybe you used the formula : f'(x) = (u'v - v'u)/(v^2) so lets calculate it : u' = 1 v' = 1 so u'v = 1*(x-1) v'u = 1*(x+1) v^2 = (x-1)^2 u'v - v'u = x-1 -(x+1) = -2 put all together : f'(x) = -2/((x-1)^2)
so i was correct.
yes :) now ive noticed lol i could spare time :|
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