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Need help with solving this and show steps please sqrt{10-3x=x
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\[\sqrt{?10-3x=x}\]
\[\sqrt{10-3x}=x\] you mean, right?
yes
square both sides: \[10-3x=x^2\] rewrite as \[x^2+3x-10=0\] factor if possible (here it is, otherwise you need the quadratic equation) \[(x+5)(x-2)=0\] x={-5,2} get it?
yes! thank you
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no prob. that'll be one medal please :)
I didnt know you can give medals
what is the meaning of that?
\[7x-4\le 4+5x\]
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