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OpenStudy (anonymous):
Use the quadratic formula to solve the equation: -3y^2=6y-10 (this goes to): -3y^2-6y+10=0 See if i got it right please, my answer was: -1+-2 sqrt. 39/-6
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OpenStudy (anonymous):
\[-1\pm(2\sqrt{39})/(-6)\] is correct.
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