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x+1(lessthan or = to >) 2x+5 what is the solution set?
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\[x+1\leq2x+5?\]
> this way
\[x+1\ \ge2x+5\]?
\[x+1\geq2x+5!?\]
yes
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\[-4\ge x\]
subtract like terms on each side
thats not it though
(-4,infiniti????)
\[x+1\geq2x+5\]\[1\geq x+5\]\[-4\geq x\]Therefore, the solution set is\[\{x\in\mathbb{R}:x\leq-4\}\]or similarly\[(-\infty,-4]\]
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so they are the same, it's just a notation thing.
Correct.
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