Question

x^2+6x-2=0

Answer 1

solve?

\[x^2+6x+9=-2+9\]\[(x+3)^2=7\]\[x=-3 \pm \sqrt{7}\]

Answer 2

\[x ^{2}+6x-2=0\]

Answer 3

solve please

Answer 4

it is solved in my first post

Answer 5

not all the way i need the x=\[\pm\]

Answer 6

i need the minus answer and plus answer

Answer 7

\[x=-3-\sqrt{7} \ or\ x=-3+\sqrt{7}\]