Question

8(t+2)-3(t-4)=6(t-7)+8

Answer 1

8(t+2)-3(t-4)=6(t-7)+8



8t+16-3t+12=6t-42+8



28+5t=6t-42+8



28+5t=-34+6t



5t=-34+6t-28



5t-6t=-34-28



-t=-34-28



-t=-62



t=-62/(-1)



t=62

Answer 2

Jim is correct. \[8(t+2)-3(t-4)=6(t-7)+8\]\[8t+16-3t+12=6t-42+8\]\[5t+28=6t-34\]\[62=t\]