Question

Find the intersection points of the graph of y=x^2 and 2+y=-3x

Answer 1

solve for y: y=-3x-2
then equate: -3x-2=x^2
x^2+3x+2=0
(x+2)(x+1)=0
x=-2 or x=-1

then you can back sub for the y-values

Answer 2

y=-3(-2)-2=6-2=4 --> (-2,4)
y=-3(-1)-2=3-2=1 --> (-1, 1)

Answer 3

or
y=(-2)^2=4 --> (-2,4)
y=(-1)^2=1 --> (-1,1)