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Find the derivative y=(6x-1)(5x-2)^-1
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I used the quotient rule- -7/(6x-1)^2
tnx
can u show the work
\[\left(\begin{matrix}(6x-1) \\ (5x-2)\end{matrix}\right)=\left(\begin{matrix}(6)(5x-2)-(6x-1)(5) \\ (5x-2)^{2}\end{matrix}\right)=\left(\begin{matrix}30x-12-30x+5 \\ (5x-2)^{2}\end{matrix}\right)=\left(\begin{matrix}-7 \\(5x-2)^{2}\end{matrix}\right)\]
i got it wrong its actually -7/(5x-2)^2
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