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Mathematics 17 Online
OpenStudy (anonymous):

integration of 1/z^2

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=int+1%2Fz^2

OpenStudy (anonymous):

-1/z +c

OpenStudy (anonymous):

if u integrate w.r.t. z

OpenStudy (anonymous):

The answer is (-1/z) + c because we can rewrite 1/z^2 as z^(-2) and it is a lot easier to see from there on

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