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Mathematics 16 Online
OpenStudy (anonymous):

integration of (1/z)^2

OpenStudy (anonymous):

You already asked this, and got a very clear answer. If you don't understand how to get it, ask specific questions to clarify.

OpenStudy (anonymous):

^ what he said See your previous post at http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e82b6950b8bc11dd547b34f

OpenStudy (anonymous):

-1/z +c

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