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\sqrt[5]{256}div sqrt[6]{64} = 2^{x}
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\[\sqrt[5]{256}\div \sqrt[6]{64} = 2^{x}\]
256 = 2^8 64 = 2^6 (2^8)^1/5 / (2^6) ^1/6 = 2^x 2^(8/5) / 2^1 = 2^x 2^(8/5 - 1) = 2^x 2^(3/5) = 2^x x= 3/5
Crap, i forgot to drop the exponent of 1 from the denominator.... Thanks sector.
by drop i mean bring it with for the rest of the party.
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