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12r^2+4r-8
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12r^2+4r-8=0? or do you need to decompose?
I need to factor it as a trinomial.
12r^2+4r-8= 12r^2+4r-8=0 than D=4^2-4*12*(-8)=16+384=400 right? r1=(-4-20)/24=-1 and r2=(-4+20)/24=16/24=2/3 yup? 12r^2+4r-8=12(r+1)(r-2/3)
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