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mn^2-49
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are you required to solve, for what m or n..extra info would be nice
@sake30 - in order to avoid problems it would be better if you wrote the first term as (mn)^2 if thats what its supposed to be. As it is it looks like m times n^2.
(mn-9)(mn+9)??? should be (mn-7)(mn+7)
that's how it was given , it says to factor each trinomial.
so u should have written factorize mn^2-49
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what 's the answer?
(mn-7)(mn+7)
(mn)^2 ?, so both m and n are squared
yep
but the question is ambiguous mn^2 could also mean m times n^2 it was best written as (mn)^2
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u r right but we know it shud be that
thank you guys for your help.
np
yw
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