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simplify: ((x^6y^3)^-1/3)/(x^4y^2)^-1/2
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\[\left( x ^{6}y ^{3} \right)^{-1/3}\div \left( x ^{4}y ^{2} \right)^{-1/2}\]
I've posted all my solutions....
\[(1/x ^{2y})/(1/x ^{2}y)=(1/x ^{2}y) * x ^{2}y=1\]
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