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HELP! A rectangle's area is A=4²ft. and the width is W=L-3ft. What is the length(L) and width (W). Please show your work so I will understand how you got the answer. Thank you!
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The area is 4^2
gah. sorry missed that. I'll delete and repost.
Method is the same though, just change the numbers.
I had (l=7)(L=-1) Didn't get the method
Are you sure it doesn't say: \[4ft^2\] ? Because that is not the same as \[4^2\]
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yes it did!
Okay, so what I posted originally is right: Given A = 4ft^2 A = L * W W = L - 3 So: \[L^2-3L-4=0\] \[(L-4)(L+1)=0\] So, L = 4 or -1 Length can't be negative, so L = 4. W = L - 3 = 4 - 3 = 1. Make sense?
Yes, Thanks!
Cool.
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