two stones are thrown vertically upward from the ground, one with 3 times the initial speed the other. If the faster stone takes 10s return to the ground , how long will the slower stone take ?
So you have an equation here. The faster stone is 3 times as fast, so each time the faster one moves 10 seconds, the slow one has to be 3 times slower than 10 seconds. Do you understand?
Can you show me the steps to do it? Which formula to use ?
I don't really use a formula. You only know that one is 3times faster than the other, and he takes 10 seconds, then that means that the other is 3 times slower. If you run 4 blocks when I run 1, and you have completed your 4 blocks in 1 hour, then I will take 4 hours to complete 1 block. Do you understand now?
this is a physics problem dude..tell me the steps dude :P
velocity = distance / time, time = distance/ velocity Here you only know time. Distance and velocity are unknown. You do know the relationship between to two speeds: speed1 = 3*speed2 Time relation: time1 = 1/3 time2: time2 = 3* time1 =....
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