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OpenStudy (anonymous):
Suppose f is differentiable at x=a and g(x)=xf(x). Show that g'(a)=af'(a)+f(a)
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OpenStudy (turingtest):
\[g'(x)=(1)f(x)+(x)f'(x)\] (product rule) now sub in for a
OpenStudy (turingtest):
\[g'(a)=f(a)+af'(a)\]
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