Question

my equation is y=0.5xcubed + 2xsquared+1xto the 4th. i know how to find the y intercepts but i cant remember how to find the x intercept. and i need help finding the max and min because i think i did it wrong

Answer 1

how did you do it?

Answer 2

\[y = 0.5x^3 + 2x^2 + x^4\]

Answer 3

x intercept is when y=0
\[y=0.5x^3+2x^2+x^4=0=x^2(0.5x+2x^2+1)\]

Answer 4

\[=0.5x^2(4x^2+x+2)\]
so y-int =0 and whatever the solutions to that quadratic are
2x^2+0.5x+1=0

Answer 5

max/min are when the derivative f'(x)=0, so\[y'=1.5x^2+4x+4x^3=x(x^3+1.5x+4)=0\]