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(x+0,2)^2-(x-0,2)^2=?
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are you squaring ordered pairs?
i got 0
The book says the answer is 0.8x but I cant seem to make it work on paper
(x+0.2)^2-(x-.02)^2 =(x^2+0.4x+0.04)-(x^2-0.4x+0.04) =x^2+0.4x+0.04-x^2+0.4x-0.04 =0.8x There is no such thing as multiplying ordered pairs, I was just making fun of the fact that you put commas instead of points in your question.
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